) OTHER EXPERIMENTAL DESIGNS JH 19.6 ILLUSTRATIVE EXAMPLE OF TWO-FACIOR EXPERIMENT WITH REPEATED MEASUREMENTS 311
j The totals above are obtained by adding the cell totals over subjects.
H Thus4 £6£1424£541< 19, and so on. Totals for rows T, ., for col-
i umns 7.., and the grand total are shown. The totals for rows by subjects
peated-measurement boj summed over columns are as follows:
r 2 X 3 — 6 treatment kO?
5 | T,,
bo: Subjects T,
ubject 2 E i
C, C, Z | 117
E H Rows
oi 79
bo! T, 1965 T,
d | Here the number 16 in the top left cell is obtained by summing the
E cells for the first subject over columns; thus 4 45-47. 16. Likewise
4 l£4 -t£2—7,andsoon. The totals for columns by subjects summed over
šč | rows, T..,, are as follows:
ij | Ta
] Subjects To.
4 34
Columns 79
š 83
m | T, 196 < 7

Here the values in the left-hand column in the above table are obtained by
summing the cells for the first subject over rows; thus 4 £ | < 5,5 4 4— 9,
K 7-£ 2 — 9, and so on.

d Use is now made of the computational formulas given in Section 17.8.
E In the present example z — 1. Also a slight notational change has been
z made. In this example layers are subjects and the symbol S is used instead
3 of L. In the formulas to foilow S is the same as L in the formulas of Section

down the totals for JE 17.8. The factor S has N levels, where N is the number of subjects.
bjects summed over 4 First we calculate eig/it guantities which are used in the computation
. Viewing the data š formulas. For this illustrative example these are as follows:
surface of the cube. ;
T,.., are as follows: 4 NE Ti — NIN x 19,930 < 1.107.22
ČN > "" 3x6 vo me
€
NE Š, Ti, | Z X 14,286 — 1,190.50
N
ze NTi. — zz X 6692 — 1,115.33
LEE. l
wo X Tiho. z X 7,456 — 1,242.67